If the volume of a confined gas is doubled (with no addition of gas) and temperature remains constant, what will happen to the pressure?

If the volume of a confined gas is doubled (with no addition of gas) and temperature remains constant, what will happen to the pressure?

• A. It will remain the same
• B. It will double
• C. It will be reduced to one-fourth
• D. It will be reduced to one-half

Answer: (D)

In a scenario where the volume of a confined gas is doubled while the temperature remains constant, the relationship governing this situation can be explained by Boyle's Law. Boyle's Law states that for a given amount of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. This means that if the volume increases, the pressure must decrease to maintain the constant temperature. When the volume is doubled, you effectively increase the space available for the gas molecules to move around. Because the gas molecules have more space to occupy, they collide with the walls of the container less frequently, which results in a reduction of pressure. Mathematically, if the initial volume is V1 and the pressure is P1, and the new volume becomes V2 (which is 2V1), then the new pressure P2 can be derived from Boyle's Law: P1 * V1 = P2 * V2 Reorganizing this gives: P2 = P1 * (V1 / V2) Substituting V2 with 2V1 results in: P2 = P1 * (V1 / (2V1)) P2 = P1 / 2 This demonstrates that the new pressure is half

In a scenario where the volume of a confined gas is doubled while the temperature remains constant, the relationship governing this situation can be explained by Boyle's Law. Boyle's Law states that for a given amount of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. This means that if the volume increases, the pressure must decrease to maintain the constant temperature.

When the volume is doubled, you effectively increase the space available for the gas molecules to move around. Because the gas molecules have more space to occupy, they collide with the walls of the container less frequently, which results in a reduction of pressure. Mathematically, if the initial volume is V1 and the pressure is P1, and the new volume becomes V2 (which is 2V1), then the new pressure P2 can be derived from Boyle's Law:

P1 * V1 = P2 * V2

Reorganizing this gives:

P2 = P1 * (V1 / V2)

Substituting V2 with 2V1 results in:

P2 = P1 * (V1 / (2V1))

P2 = P1 / 2

This demonstrates that the new pressure is half